Hi Jim,
I hoped that there’s some solution using the range notation like you showed:
With named association, you can also do the following:
A <= RndA.DistSlv((0=>5, 1 to 14 =>1, 15=>5), A'length) ;
I just didn’t expect it to be so straight simple, since the defined type is self defined.
You mentioned integer_vectors somewhere else. Are these defined internally in a similar way as DistValSlv is? Does this kind of assignment work with integer_vectors too?
Kind regards
Eilert
